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Simplifying b3c + 26b2c + 169bc = 0 Reorder the terms: 169bc + 26b2c + b3c = 0 Solving 169bc + 26b2c + b3c = 0 Solving for variable 'b'. Factor out the Greatest Common Factor (GCF), 'bc'. bc(169 + 26b + b2) = 0 Factor a trinomial. bc((13 + b)(13 + b)) = 0Subproblem 1
Set the factor 'bc' equal to zero and attempt to solve: Simplifying bc = 0 Solving bc = 0 Move all terms containing b to the left, all other terms to the right. Simplifying bc = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.Subproblem 2
Set the factor '(13 + b)' equal to zero and attempt to solve: Simplifying 13 + b = 0 Solving 13 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '-13' to each side of the equation. 13 + -13 + b = 0 + -13 Combine like terms: 13 + -13 = 0 0 + b = 0 + -13 b = 0 + -13 Combine like terms: 0 + -13 = -13 b = -13 Simplifying b = -13Subproblem 3
Set the factor '(13 + b)' equal to zero and attempt to solve: Simplifying 13 + b = 0 Solving 13 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '-13' to each side of the equation. 13 + -13 + b = 0 + -13 Combine like terms: 13 + -13 = 0 0 + b = 0 + -13 b = 0 + -13 Combine like terms: 0 + -13 = -13 b = -13 Simplifying b = -13Solution
b = {-13, -13}
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